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5x-2x^2+127=0
a = -2; b = 5; c = +127;
Δ = b2-4ac
Δ = 52-4·(-2)·127
Δ = 1041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{1041}}{2*-2}=\frac{-5-\sqrt{1041}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{1041}}{2*-2}=\frac{-5+\sqrt{1041}}{-4} $
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